# How do you solve # 3x^2 - 14x - 5 = 0#?

##### 2 Answers

#### Explanation:

You could solve this quadratic equation by using the *quadratic formula*.

For a quadratic equation that takes the general form

#color(blue)(ax^2 + bx + c = 0)#

the two solutions can be determined by using the *quadratic formula*

#color(blue)(x_(1,2) = (-b +- sqrt(b^2 - 4ac))/(2a)#

In your case,

Solve y = 3x^2 - 14x - 5 = 0 (1)

Ans: (- 1/3) and (5).

#### Explanation:

I use the new Transforming Method.

Transformed y' = x^2 - 14x - 15 = 0. (2)

Since (a -b + c = 0) --> 2 real roots of (2) are (-1) and (-c/a = 15).

Back to equation (1), the 2 real roots are: