How do you solve -(3x + 2) = -19x + 62?

Jul 18, 2015

$x = 4$

Explanation:

We're trying to get $x$ alone. We need to find ways to manipulate the equation such that we can put all the $x$'s on one side of the equation.

Let's distrubute the negative outside the parenthesis first (you can equivalently divide by -1 on both sides of the equation)

$- \left(3 x + 2\right) = - 3 x - 2 = - 19 x + 62$

Now, we can add the $19 x$ to both sides of the equation so that we're getting rid of it on the right side.

$- 3 x + 19 x - 2 = \left(- 19 x + 19 x\right) + 62$

$16 x - 2 = 62$

We're close to getting $x$ alone. We can add the $2$ to both sides now so that it cancels out on the left side.

$16 x = 62 + 2 = 64$

Now, all we need to do is divide by $16$ on both sides of the equation to get the value of $x$.

$x = \frac{64}{16} = 4$