How do you solve #-3x^2=2(3x-5)# using the factoring method?

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Answer 1 · 2016-08-24T15:50:18

There are no factors which give -6.
Therefore, this equation cannot be solved using the factor method.

First simplify and get rid of the brackets:

#-3x^2 = 6x-10" make it" = 0#

#0 = 3x^2+6x-10#

All the information we need is in the quadratic expression.

#3xx10 = 30#

Find factors of 30 which subtract to make 6.
The signs will be different and there are more positives.

Factors of 30#rarr# (difference)

#1xx30 rarr(29)#
#2xx15rarr(13)#
#3xx10rarr(7)#
#5xx6rarr(1)#

There are no factors which give 6.
Therefore, this equation cannot be solved using the factor method.