How do you solve $3x-2(2-x)=6-x-10$ ?

Question

1910 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-11T05:41:28

$x = 0$

$3x - 2 ( 2 -x ) = 6 - x - 10$

$3x - color(green)((2 )) * ( 2) + color(green)( (-2)) * ( -x ) = 6 - x - 10$

$3x - 4 + 2x = - x - 4$

$5x - 4 = - x - 4$

$5x + x = - 4 + 4$

$6x = 0$

$x = 0/6$

$x = 0$

How do you solve 3x-2(2-x)=6-x-103x-2(2-x)=6-x-10?