How do you solve #3x^2 + 2x - 5 = 0#?

1 Answer
May 7, 2016

Answer:

#(3x + 5) = 0#

#x= - (5/3)#

#x - 1 = 0#
#x= 1#

Hence, solution is #x = -(5/3) or x=1#

Explanation:

The question gives you an equation #3x^2 + 2x -5 = 0#.

Hence to solve the equation, factorise.

#3x^2 + 2x -5 = 0#
#(3x + 5)(x -1) = 0#

The 2 factors of the equation are #(3x + 2) and (x - 1).#

With #(3x + 5) = 0 # and #(x - 1) = 0#
Solve for #x# to find the solutions.