How do you solve #3x^2+ 2x = 8# by factoring?

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Answer 1 · 2015-08-12T01:39:31

#x=4/3# and #x=-2#

Subtract #8# from both sides

#3x^2+2x-8=0#

This will factor into

#(3x-4)(x+2)=0#

So

#3x-4=0# or #x+2=0#

Solving each of these

#3x=4#

#x=4/3#

#x+2=0#

#x=-2#