How do you solve #3x^2+45=24x# by factoring? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Suren Abreu Oct 26, 2016 #x=5#, #3# Explanation: #3x^2+45=24x# #3x^2-24x+45=0# Factorise. #3x^2-9x-15x+45=0# #3x(x-3)-15(x-3)=0# #(3x-15)(x-3)=0# #3x-15=0# and #x-3=0# #:.x=15/3=5# and #x=3# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2826 views around the world You can reuse this answer Creative Commons License