# How do you solve 3x^2 + 4x = 2  using the quadratic formula?

Aug 3, 2018

$x = \frac{- 2 + \sqrt{10}}{3}$, $x = \frac{- 2 - \sqrt{10}}{3}$

#### Explanation:

$3 {x}^{2} + 4 x = 2$

First, make one side equal to zero by subtracting $\textcolor{b l u e}{2}$ from both sides:
$3 {x}^{2} + 4 x - 2 = 0$

The quadratic formula is $x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$, where from our equation we know that $a = 3 , b = 4 , \mathmr{and} c = - 2$.

Plug them into the formula:
$x = \frac{- 4 \pm \sqrt{{4}^{2} - 4 \left(3\right) \left(- 2\right)}}{2 \left(3\right)}$

$x = \frac{- 4 \pm \sqrt{16 + 24}}{6}$

$x = \frac{- 4 \pm \sqrt{40}}{6}$

$x = \frac{- 4 \pm 2 \sqrt{10}}{6}$

$x = \frac{- 2 \pm \sqrt{10}}{3}$

Hope this helps!