# How do you solve 3x^2-4x=4?

Jun 17, 2015

 color(green)( x=-2/3 and x=2

#### Explanation:

Here, we can first factorise the expression and thereby find the solutions:

Factorising by splitting the middle term
$3 {x}^{2} - 4 x - 4 = 0$
$3 {x}^{2} - 6 x + 2 x - 4 = 0$
$3 x \left(x - 2\right) + 2 \left(x - 2\right) = 0$
color(green)( (3x+2)(x-2) =0

Equating the factors with zero
$3 x + 2 = 0 , x = - \frac{2}{3}$
$x - 2 = 0 , x = 2$

So the solutions are:
 color(green)( x=-2/3 and x=2