# How do you solve 3x^2-5x+4=0 using the quadratic formula?

May 11, 2016

$x = \frac{5 \pm i \sqrt{23}}{6}$
$y = 3 {x}^{2} - 5 x + 4 = 0$
$D = {d}^{2} = {b}^{2} - 4 a c = 25 - 48 = - 23 = 23 {i}^{2}$ --> $d = \pm i \sqrt{23}$
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = \frac{5}{6} \pm i \frac{\sqrt{23}}{6} = \frac{5 \pm i \sqrt{23}}{6}$