Question

How do you solve `3x^2-5x+4=0` using the quadratic formula?

Answer 1

`x = (5 +- isqrt23)/6`

Explanation:

`y = 3x^2 - 5x + 4 = 0`
Use the improved quadratic formula.
`D = d^2 = b^2 - 4ac = 25 - 48 = - 23 = 23i^2` --> `d = +- isqrt23`
There are no real roots. There are 2 complex roots:
`x = -b/(2a) +- d/(2a) = 5/6 +- isqrt23/6 = (5 +- isqrt23)/6`