How do you solve #3x^2-8x=0#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Aviv S. Mar 4, 2018 The answers are #x=0, 8/3#. Explanation: Factor out the #x# term, and then set each factor each to zero. #3x^2-8x=0# #color(red)x*color(blue)(3x)-color(red)x*color(blue)8=0# #color(red)x(color(blue)(3x-8))=0# #color(white){color(black)((color(red)x=0, qquadqquad color(blue)(3x-8)=0), (color(red)x=0, qquadqquad color(blue)(3x)=8), (color(red)x=0, qquadqquad color(blue)x=8/3):}# So the solutions are #x=0, 8/3#. Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 9400 views around the world You can reuse this answer Creative Commons License