How do you solve #-3x^2 + 9x = 0#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Don't Memorise Jun 23, 2015 #color(green)(x= 0 or x = 3# Explanation: #-3x^2 + 9x = 0# Here, #3x# is a common factor: #3x(-x +3) = 0# #3x = 0 or (-x +3) = 0# #color(green)(x = 0 or x= 3# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 5211 views around the world You can reuse this answer Creative Commons License