How do you solve $3 x^{2} - x = 10$ $3x^2-x= 10$ ?

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Answer 1 · 2016-08-12T06:02:09

$x = {- \frac{5}{3}, 2}$ $x={-5/3,2}$

$3 x^{2} - x = 10 ?$ $3x^2-x=10 ?$

$Rearrange the equation$ $"Rearrange the equation "$

$3 x^{2} - x - 10 = 0$ $3x^2-x-10=0$

$Factor the equation as$ $"Factor the equation as "$

$(x - 2) (3 x + 5) = 0$ $(x-2)(3x+5)=0$

$(x - 2) = 0; \to x = 2$ $(x-2)=0 " ; " rarr x=2$

$(3 x + 5) = 0; \to x = - \frac{5}{3}$ $(3x+5)=0" ; "rarr x=-5/3$

$x = {- \frac{5}{3}, 2}$ $x={-5/3,2}$

How do you solve 3x2−x=103x^2-x= 10?