How do you solve #3x² = 2x +4#?

1 Answer
Jan 20, 2017

Answer:

First, rewrite it as #3x^2-2x-4=0#, then use the quadratic formula and you find the roots to be #x=(1+-sqrt13)/3#

Explanation:

Once you have it in the form #3x^2-2x-4=0#, the quadratic formula gives a reliable means of finding the roots:

#x=(2+- sqrt((-2)^2-4(3)(-4)))/(2(3))=(2+-sqrt52)/6=(2+-2sqrt13)/6#

Now, just divide each term by 2:

#x=(1+-sqrt13)/3#