# How do you solve 3x + 2y = -2 and -2x - 4y = 0?

Sep 6, 2015

$x = - 1$
$y = \frac{1}{2}$

#### Explanation:

$3 x + 2 y = - 2 \text{ " " } \left(1\right)$
$- 2 x - 4 y = 0 \text{ " " } \left(2\right)$

Solve equation $\left(2\right)$ for $y$

$- 4 y = 2 x$

$y = \frac{2 x}{-} 4 = \frac{- x}{2}$

Substitute $y = \frac{- x}{2}$ in equation $\left(1\right)$

$3 x + 2 \cdot \left(\frac{- x}{2}\right) = - 2$

$3 x - x = - 2$

$2 x = - 2$

$x = \frac{- 2}{2} = - 1$

$x = - 1$

Substitute $x = - 1$ in equation $\left(1\right)$

$3 \left(- 1\right) + 2 y = - 2$

$- 3 + 2 y = - 2$

$2 y = - 2 + 3 = 1$

$y = \frac{1}{2}$