How do you solve #3x - 2y = 4# and #y = 2x - 6#?

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Answer 1 · 2015-08-04T05:54:02

The solution for the system of equations is
#color(blue)(x=8,y=10#

#3x−2y=4#.....equation #(1)#
# y=color(blue)(2x−6#.......equation #(2)#

Solving through substitution

Substituting equation #(2)# in equation #(1)#
#3x−2*(color(blue)(2x−6))=4#

#3x−4x +12=4#

#-x +12=4#
#color(blue)(x=8#

Finding #y# by substituting #x# in equation #2#
# y=2x−6#

# y=2*8−6#

# y=16−6#

#color(blue)(y=10#