How do you solve 3x + 3< x + 63x+3<x+6?

1 Answer
Apr 26, 2018

x<3/2x<32 or x<1.5x<1.5

Explanation:

Given: 3x+3<x+63x+3<x+6.

Subtract xx from both sides.

3x+3-x<color(red)cancelcolor(black)x+6-color(red)cancelcolor(black)x

2x+3<6

Subtract 3 from both sides.

2x+color(red)cancelcolor(black)3-color(red)cancelcolor(black)3<6-3

2x<3

Divide by 2 to get x.

(color(red)cancelcolor(black)2x)/(color(red)cancelcolor(black)2)<3/2

x<3/2=1.5