# How do you solve 3x + 3< x + 6?

##### 1 Answer
Apr 26, 2018

$x < \frac{3}{2}$ or $x < 1.5$

#### Explanation:

Given: $3 x + 3 < x + 6$.

Subtract $x$ from both sides.

$3 x + 3 - x < \textcolor{red}{\cancel{\textcolor{b l a c k}{x}}} + 6 - \textcolor{red}{\cancel{\textcolor{b l a c k}{x}}}$

$2 x + 3 < 6$

Subtract $3$ from both sides.

$2 x + \textcolor{red}{\cancel{\textcolor{b l a c k}{3}}} - \textcolor{red}{\cancel{\textcolor{b l a c k}{3}}} < 6 - 3$

$2 x < 3$

Divide by $2$ to get $x$.

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} x}{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}}} < \frac{3}{2}$

$x < \frac{3}{2} = 1.5$