# How do you solve 3x + 4y = 7 and 5x - 2y = 16?

Jul 17, 2015

I found:
$x = 3$
$y = - \frac{1}{2}$

#### Explanation:

I would multiply the second equation by $2$ and add the two equations (in columns):
{3x+4y=7
{color(red)(10x-4y=32 adding:
$13 x + 0 = 39$
$x = \frac{39}{13} = 3$
Substitute back this value of $x$ into the first equation:
$3 \cdot 3 + 4 y = 7$
$9 + 4 y = 7$
$4 y = - 2$
$y = - \frac{1}{2}$