How do you solve #-3x+5> -7#? Algebra Linear Inequalities and Absolute Value Inequalities with Multiplication and Division 1 Answer unknown · Stefan V. May 11, 2018 Answer: #x < 4# Explanation: #-3x + 5 > -7# Subtract #5# to the RH side. After subtracting #5#, you end up getting #-3x > -12# Divide by #-3# into both sides #x < 4# And since you divided both sides by negative, you switch the sign. Related questions How do you solve inequalities using multiplication and division? How do you solve two step inequalities? Why do you change the inequality symbol when you multiply or divide by a negative? How do you solve for x in #-10x > 250#? How do you solve and graph #\frac{x}{5} > - \frac{3}{10}#? What is the solution to #\frac{x}{-7} \ge 9# written in set notation? Why do you not change the inequality sign when solving #9x > - \frac{3}{4}#? How do you graph #\frac{k}{-14} \le 1# on a number line? How do you graph #8d < 24#? How do you graph #-8d < 24#? See all questions in Inequalities with Multiplication and Division Impact of this question 217 views around the world You can reuse this answer Creative Commons License