How do you solve #3x-51=-2x+59#?

2 Answers

#x= 22#

Explanation:

1) Combine Like terms by transposition of terms. [Remember to reverse the signs when transposing]

#3x - 51 = - 2x + 59 #

By combining like terms, you should get

#3x + 2x = 110 + 51#

#rArr 5x = 110#

2) Divide by #5# on both sides and you will get the answer.

#5x = 110#

#rArr x= 22#

22

Explanation:

This is a topic of mathematical transpositions. The main goal of transposing is grouping variables and constants on different sides for easier evaluation without disrupting the equality of the whole system/equation.

For this example, we can group all terms with the #x# variables at one side, let's say the left side and also group all constants or terms without variables on the right side.

This would specifically mean that #-2x# will be transposed onto the left side and #-51# will be transposed onto the right side. As a result, the equation will yield:
#3x+2x=59+51#

Simplifying,
#5x=110#

Solving for #x#;
#x=frac110 5=22#

Take note that the transposed terms #-2x# and #-51# have changed their signs after transposing. This is true to maintain the equality of the whole equation.

For example,
#5+8=13#
If we transpose #8# onto the other side of the equation, the whole equation becomes
#[5 =13-8]# or #[5=-8+13]#
And we can see that the equality of the whole equation is maintained. In essence, the mathematical operation performed in the transposition can be done by subtracting #8# (or adding #-8#) on both sides:
#(5+8)-8=(13)-8#
#5=13-8#