# How do you solve 3x-5y=14 and x+4y=10?

Aug 10, 2015

I found:
$x = \frac{106}{17}$
$y = \frac{16}{17}$

#### Explanation:

You can try isolate $x$ from the second equation and substitute into the first:
$x = 10 - 4 y$
into the first:
$3 \left(10 - 4 y\right) - 5 y = 14$ solve for $y$:
$30 - 12 y - 5 y = 14$
$- 17 y = - 16$
$y = \frac{16}{17}$
substitute this back into the the equation: $x = 10 - 4 y$ to find:
$x = 10 - 4 \cdot \frac{16}{17} = \frac{106}{17}$