# How do you solve #(3x-6)^2= 4x^2?

Feb 5, 2015

${\left(3 x - 6\right)}^{2} = 4 {x}^{2}$

You can take the square root of both sides, in other words cancel out the squares.

BUT:
Remember the $+$ and $-$ signs!

Because ${a}^{2} = {b}^{2}$ may mean that $a = b$
it can also mean that $a = - b$
(squared they are both positive!)

So we get:

$3 x - 6 = + 4 x \mathmr{and} 3 x - 6 = - 4 x$

These solve for $x = - 6 \mathmr{and} x = + \frac{6}{7}$