# How do you solve 3x + 7y = 5 and 5x - 9y = -5?

Mar 8, 2018

$x = \frac{5}{31}$ $y = \frac{20}{31}$

#### Explanation:

$8 x - 2 y = 0$
$8 x = 2 y$
$y = 4 x$
So $3 x + 7 \left(4 x\right) = 5$
$31 x = 5$
$x = \frac{5}{31}$
Since $y = 4 x$
$y = 4 \cdot \frac{5}{31} = \frac{20}{31}$