How do you solve $3x+8=32$ ?

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Answer 1 · 2015-06-28T19:06:29

The answer will be
$x=8$

First, we will take the $+8$ to the RHS. As it is positive, sending to RHS will make it negative. Therefore

$3x=32-8$
$3x=24$

Now we will send 3 to the RHS. As 3 is in multiply, sending it to RHS will make it a divisor.

$x= 24/3$

Hence

$x=8$

How do you solve 3x+8=323x+8=32?