How do you solve #3x (8x-1)(x+9)=0#?

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Answer 1 · 2017-08-05T04:48:43

#x=0# or #x=1/8# or #x=-9#

#3x(8x-1)(x+9)=0# shows that

product of #3#, #x#, #(8x-1)# and #(x+9)# is zero i.e. #0#.

As #3# is not zero,

either #x=0# or #8x-1=0# or #x+9=0#

if #8x-1=0#, then we have #8x-1color(red)(+1)=0color(red)(+1)#

i.e. #8x=1# i.e. #1/8xx8x=1/8xx1# or #x=1/8#

or #x=1/8#

and if #x+9=0#, #x+9color(red)(-9)=0+color(red)(-9)# or #x=-9#

i.e. either #x=0# or #x=1/8# or #x=-9#