How do you solve #(3x )/ (x+1) = 12 / (x-1)#?

1 Answer
Apr 25, 2018

Answer:

the answer is #x=(5+sqrt(41))/(2), (5-sqrt(41))/(2)#

Explanation:

first you have to cross multiply and you get: #12x+12=3x^2-3x# and now move all the terms to one side to make it equal to zero. #3x^2-15x-12=0# and you can take out #3# from all numbers so: #3(x^2-5x-4)=0# since you can't factor the parenthesis equation, you have to use the quadratic formula which is: #(-bsqrt(b^2-4ac))/(2a)# and put in the respectful numbers in:#-(-15)sqrt(4(3)(-12))/(2(3))# and now solve to get your answer