# How do you solve (3x)/(x+1) = (3x-2)/(x+2)?

$\frac{3 x}{x + 1} = \frac{3 x - 2}{x + 2} \implies 3 x \left(x + 2\right) = \left(3 x - 2\right) \left(x + 1\right) \implies 3 {x}^{2} + 6 x = 3 {x}^{2} + 3 x - 2 x - 2 \implies 5 x = - 2 \implies x = - \frac{2}{5}$