How do you solve #3x(x-2)=25+4x^2-4x#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Guillaume L. May 18, 2018 #x notin RR# Explanation: #3x(x-2)=25+4x²-4x# #3x²-6x=25+4x²-4x# #0=x²+2x+25# #Δ=2²-4*25# #Δ=-96# so #x notin RR# \0/ here's our answer! Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1570 views around the world You can reuse this answer Creative Commons License