# How do you solve 3x(x-5)=0?

Since both terms are being multiplied to give 0, one of them has to be 0, so either $3 x = 0$ or $x - 5 = 0$, if $3 x = 0 , x = 0$ and if $x - 5 = 0 , x = 5$
So either $x = 0$ or $x = 5$