# How do you solve 3x-y=12 and 5x+2y=20?

Feb 18, 2016

x=4; y =0

#### Explanation:

$3 \cdot x - y = 12 \left(1\right)$
$5 \cdot x + 2 \cdot y = 20 \left(2\right)$
Multiplying (1) by 2 we get
$6 \cdot x - 2 \cdot y = 24$ (1)
$5 \cdot x + 2 \cdot y = 20 \left(2\right)$
Adding (1) & (2) we get
$11 \cdot x = 44 \mathmr{and} x = 4$ putting x=4 in (1) we get $y = 3 \cdot 4 - 12 = 0$
So x=4; y =0  ;[Answer]