How do you solve 3x+y=3 and 2x+3y=-5?

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Answer 1 · 2015-09-05T07:34:11

The solution is
#color(blue)(x=2,y=-3#

# 3x+y=3 #, multiplying the equation by #3#
# 9x+color(blue)(3y)=9 #........equation #1#

# 2x+color(blue)(3y)=-5#....equation #2#

Solving by elimination as subtracting the two equations eliminates #color(blue)(3y#

Subtracting equation #2# from #1#
# 9x+cancelcolor(blue)(3y)=9 #

#- 2x-cancelcolor(blue)(3y)=+5#

#7x=14#
#color(blue)(x=2#

Finding #y# by substituting #x# in equation #1#
# 3x+y=3 #
# y=3-3x #
# y=3-3*2 #
# y=3-6 #
#color(blue)(y=-3#