# How do you solve 4-12n-14 > 8n +12 -9n?

Jan 27, 2017

$n < - 2$

#### Explanation:

First, you could transfer the n-terms to the left and the known terms to the right, taking care of changing the signs to the transferred terms:

$- 12 n - 8 n + 9 n > - 4 + 14 + 12$

then sum the like terms:

$- 11 n > 22$

then change the signs and the behavior:

$11 n < - 22$

and divide right and left terms by 11:

$n < - 2$

that's, in the interval form, if $n \in \mathbb{R}$:

n in]-oo;-2[