How do you solve #-4/15n + 2/3 = 2/5n#?

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Answer 1 · 2018-03-12T15:15:25

#n=1#

#-4/15*n+2/3=2/5*n#

#(2/5+4/15)*n=2/3#

#2/3*n=2/3#

#n=2/3*3/2#

#n=1#

Answer 2 · 2018-03-12T15:22:39

#n=1#

#-4/15n+2/3 = 2/5n" "larrxx 15# to get rid of the fractions

#-(cancel15xx4)/cancel15n+(cancel15^5xx2)/cancel3 = (cancel15^3xx2)/cancel5n#

#-4n+10 = 6n#

#-6n-4n = -10#

#" "-10n =-10#

#" "n=1#