# How do you solve 4= 2( j - 7)?

Mar 19, 2018

See a solution process below:

#### Explanation:

First, divide each side of the equation by $\textcolor{red}{2}$ to eliminate the parenthesis while keeping the equation balanced:

$\frac{4}{\textcolor{red}{2}} = \frac{2 \left(j - 7\right)}{\textcolor{red}{2}}$

$2 = \frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} \left(j - 7\right)}{\cancel{\textcolor{red}{2}}}$

$2 = j - 7$

Now, add $\textcolor{red}{7}$ to each side of the equation to solve for $j$ while keeping the equation balanced:

$2 + \textcolor{red}{7} = j - 7 + \textcolor{red}{7}$

$9 = j - 0$

$9 = j$

$j = 9$

Mar 19, 2018

$J = 9$

#### Explanation:

First, with any equation we would expand the bracket:

$2 \times j = 2 j$

$2 \times - 7 = - 14$

$\therefore$ $4 = 2 \left(j - 7\right) \to 2 = 2 j - 14$

We would like the $J$ on one side, therefore we do the opposite to $- 14$ which is to $+ 14$ to both sides.

$4 = 2 j - 14 \to 18 = 2 j$

Solve for $J$...

$j = \frac{18}{2} = 9$