How do you solve #4= 2( j - 7)#?

2 Answers
Mar 19, 2018

Answer:

See a solution process below:

Explanation:

First, divide each side of the equation by #color(red)(2)# to eliminate the parenthesis while keeping the equation balanced:

#4/color(red)(2) = (2(j - 7))/color(red)(2)#

#2 = (color(red)(cancel(color(black)(2)))(j - 7))/cancel(color(red)(2))#

#2 = j - 7#

Now, add #color(red)(7)# to each side of the equation to solve for #j# while keeping the equation balanced:

#2 + color(red)(7) = j - 7 + color(red)(7)#

#9 = j - 0#

#9 = j#

#j = 9#

Mar 19, 2018

Answer:

#J=9#

Explanation:

First, with any equation we would expand the bracket:

#2 xx j =2j#

#2 xx -7=-14#

#therefore# #4=2(j-7) -> 2=2j-14#

We would like the #J# on one side, therefore we do the opposite to #-14# which is to #+14# to both sides.

#4=2j-14 -> 18=2j#

Solve for #J#...

#j=18/2=9#