There are several ways to approach this. My first step is to multiply each side of the equation by #color(red)(1/-2)# to eliminate the negative signs and factor some of the numbers:
#color(red)(1/-2) * (-4)/(2 - x) = color(red)(1/-2) * -2#
#color(red)(1/color(black)(cancel(color(red)(-2)))) * (color(red)(cancel(color(black)(-4))) 2)/(2 - x) = color(red)(1/color(black)(cancel(color(red)(-2)))) * color(red)(cancel(color(black)(-2)))#
#2/(2 - x) = 1#
Next, multiply each side of the equation by #(color(red)(2 - x))# to eliminate the fraction while keeping the equation balanced:
#(color(red)(2 - x)) * 2/(2 - x) = 1(color(red)(2 - x))#
#cancel((color(red)(2 - x))) * 2/color(red)(cancel(color(black)(2 - x))) = 2 - x#
#2 = 2 - x#
Then subtract #color(red)(2)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#-color(red)(2) + 2 = -color(red)(2) + 2 - x#
#0 = 0 - x#
#0 = -x#
Now, multiply each side of the equation by #color(red)(-1)# to solve for #x# while keeping the equation balanced:
#color(red)(-1) * 0 = color(red)(-1) * -x#
#0 = x#
#x = 0#