How do you solve #4(2r+8)=88# using the distributive property?

1 Answer
Sep 9, 2016

Answer:

Distribute #4(2r+8)=88# to #8r+32=88# and solve.

Explanation:

Let's look at what the distributive property says first.

#a(b+c) = ab+ac#
It says we can distribute a coefficient outside parenthesis amongst the terms inside.

We see the same pattern with this equation,
#4(2r+8) = 88#
where #4# is the outside coefficient, and #2r# and #8# are the inside terms.

Therefore, we can distribute that equation as,
#4(2r+8) = 8r + 32 =88#

We can then subtract 32 from both sides,
#8r = 56#
then divide 8 from both sides to reach,
#r = 7#
which is our answer. #square#