# How do you solve #4(2y-1)=4(y+3)# for y?

##### 2 Answers

**Less thought, more mechanical:** first remove the parentheses on both sides by distributing the multiplication. Then collect all the terms involving

It looks like this:

Check your answer.

**More thought, looking at the equation:**

Instead of distributing the

#1/4*4 = [1/4 *4] (y+3)

Check your answer.

First multiply

Now, isolate the

Notice the change of sign of

now we can add and subtract:

The

hope it helps!