# How do you solve 4(3 y - 2) + 5( y + 8) = 0?

Mar 4, 2016

$y = - \frac{32}{17}$

#### Explanation:

$4 \left(3 y - 2\right) + 5 \left(y + 8\right) = 0$

$4 \times \left(3 y\right) + 4 \times \left(- 2\right) + 5 \times \left(y\right) + 5 \times \left(8\right) = 0$

$12 y - 8 + 5 y + 40 = 0$

$17 y - 8 + 40 = 0$

$17 y + 32 = 0$

$17 y = - 32$

$y = - \frac{32}{17}$