# How do you solve 4/3x^2 - 2x + 3/4 = 0  using the quadratic formula?

Jun 2, 2018

x=3/4

#### Explanation:

$a {x}^{2} + b x + c$

$\frac{4}{3} {x}^{2} - 2 x + \frac{3}{4} = 0$

I would start by multiplying the whole thing by the common denominator of the fractions: $12$ then we can just deal with integers.

$12 \left(\frac{4}{3} {x}^{2} - 2 x + \frac{3}{4} = 0\right)$

$16 {x}^{2} - 24 x + 9 = 0$

$a = 16 , b = - 24 , c = 9$

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$x = \frac{- \left(- 24\right) \pm \sqrt{{\left(- 24\right)}^{2} - 4 \cdot 16 \cdot 9}}{2 \cdot 16}$

$x = \frac{24 \pm \sqrt{576 - 576}}{32}$

$x = \frac{24}{32} = \frac{3}{4}$

graph{16x^2 -24x +9 [-9.54, 10.46, -1.2, 8.8]}