Question

How do you solve `4-3x=2x^2` using the quadratic formula?

Answer 1

We first rearrange into a proper quadratic =0 equation:

Explanation:

`2x^2+3x-4=0`

`x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`

`x_(1,2)=(-3+-sqrt(3^2-4*2*(-4)))/(2*2)`

`x_(1,2)=(-3+-sqrt(9+32))/4=-3/4+-1/4sqrt41`

graph{2x^2+3x-4 [-10.42, 9.58, -6.64, 3.36]}