# How do you solve 4|3x + 4| = 4x + 8?

Aug 23, 2016

$x = - 1 \mathmr{and} - \frac{3}{2}$.

#### Explanation:

For $x \ge - \frac{4}{3} , 3 x + 4 \ge 0$, and so, $| 3 x + 4 | = 3 x + 4$.

Substituting and solving

$x = - 1 > - \frac{4}{3}$..

For $x \le - \frac{4}{3} , 3 x + 4 \le 0$, and so, $| 3 x + 4 | = - \left(3 x + 4\right)$.

Substituting and solving

$x = - \frac{3}{2} < - \frac{4}{3}$.