How do you solve #-4 (-4+x)>56#? Algebra Linear Inequalities and Absolute Value Inequalities with Multiplication and Division 1 Answer Willow M. · Stefan V. Mar 27, 2018 Answer: #x < -10# Explanation: Distribute the #-4#. So you get #16 -4x > 56# Subtract #16# from both sides so you get #-4x > 40# Divide by #-4# on both sides and flip the #># sign because you are dividing by a negative. You will get #x < -10# Related questions How do you solve inequalities using multiplication and division? How do you solve two step inequalities? Why do you change the inequality symbol when you multiply or divide by a negative? How do you solve for x in #-10x > 250#? How do you solve and graph #\frac{x}{5} > - \frac{3}{10}#? What is the solution to #\frac{x}{-7} \ge 9# written in set notation? Why do you not change the inequality sign when solving #9x > - \frac{3}{4}#? How do you graph #\frac{k}{-14} \le 1# on a number line? How do you graph #8d < 24#? How do you graph #-8d < 24#? See all questions in Inequalities with Multiplication and Division Impact of this question 182 views around the world You can reuse this answer Creative Commons License