How do you solve $4 ^ (4x-6) = 39$ ?

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Answer 1 · 2016-04-21T19:20:15

$x=1/4 (ln39/ln4 +6)~~2.16$

$ln4^(4x-6)=ln39$

$(4x-6)ln4=ln39$

$4x-6=ln39/ln4$

$4x=ln39/ln4 +6$

$x=1/4 (ln39/ln4 +6)~~2.16$

How do you solve 4 ^ (4x-6) = 394 ^ (4x-6) = 39?