How do you solve #4 ^ (4x-6) = 39#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Bdub Apr 21, 2016 #x=1/4 (ln39/ln4 +6)~~2.16# Explanation: #ln4^(4x-6)=ln39# #(4x-6)ln4=ln39# #4x-6=ln39/ln4# #4x=ln39/ln4 +6# #x=1/4 (ln39/ln4 +6)~~2.16# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1170 views around the world You can reuse this answer Creative Commons License