Question

How do you solve `4(5b +2)-b=2+8(3b-8)`?

Answer 1

`b=14`

Explanation:

Both brackets neednto be expanded first, where `a(b+c)-=ab+ac`

This means that `4(5b+2)-=(4*5b)+(4*2)=20b+8`

It also means that `8(3b-8)-=(8*3b)+(8*-8)=24b-64`

You now have `20b+8-b=2+24b-64`. Put all b's on the left hand side and numbers on the right.

`20b+8-b=2+24b-64`
`20b-b-24b=-8+2-64`
`-5b=-70`

Now divide both sides by `-5`.

`(-5b)/(-5)=(-70)/(-5)`
`b=14`

Answer 2

`b=14`

Explanation:

`4(5b+2)-b=2+8(3b-8)`

First open the brackets and simplify by multiplying each term with the number outside the bracket.

`20b+8-b=2+24b-64`

Simplify each side.

`19b+8=24b-62`

Add `62` to each side.

`19b+70=24b`

Subtract `19b` from each side.

`70=5b`

Divide both sides by `5`.

`14=b`