Question

How do you solve `4/5x^2+1=0`?

Answer 1

`x=+-sqrt5/2i`

Explanation:

`"subtract 1 from both sides"`

`rArr4/5x^2=-1`

`rArrx^2=-5/4`

`rArrx=+-sqrt(-5/4)`

`rArrx=+-sqrt5/2i`