How do you solve #4(8-p)-(7-p)=22 #?

1 Answer
Mar 20, 2018

Answer:

#p=1#

Explanation:

#"distribute the brackets on the left side of the equation"#

#32-4p-7+p=22#

#rArr-3p+25=22#

#"subtract 25 from both sides"#

#-3pcancel(+25)cancel(-25)=22-25#

#rArr-3p=-3#

#"divide both sides by "-3#

#(cancel(-3) p)/cancel(-3)=(-3)/(-3)#

#rArrp=1#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#4(7)-(6)=28-6=22=" right side"#

#rArrp=1" is the solution"#