How do you solve #4[9^(x-1)] = 108#?

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Answer 1 · 2018-04-18T05:06:02

#x=5/2#

Here,

#4[9^(x-1)]=108#

Dividing both sides by #4#

#(4[9^(x-1)])/4=108/4#

#=>[9^(x-1)]=27#

#=>(3^2)^(x-1)=3^3#

#=>3^(2x-2)=3^3#

#=>2x-2=3#

#=>2x=5#

#=>x=5/2#