# How do you solve #4/(b+1)= 1 + 2/(2b-1)#?

##### 1 Answer

The given equation has no Real solutions

(see below for Complex solution values)

#### Explanation:

Given

Multiply both sides by

Simplify:

Re-write in standard parabolic form

Using the quadratic formula:

with no Real roots (because of the negative square root value)

but

Complex roots at

If we re-write

as

then examine the graph of left side:

graph{4/(x+1)-2/(2x-1)-1 [-10, 10, -5, 5]}

We see that at no point does it touch the X-axis (i.e. it is never equal to