Question

How do you solve `4\cdot ( x - 3) = 2x + 4`?

Answer 1

x = 8

Explanation:

`4(x-3)=2x+4`
`4x-12=2x+4`
`2x=16`
`x=8`

Answer 2

`x=8`

Explanation:

`"distribute bracket on left side of equation"`

`rArr4x-12=2x+4`

`"subtract 2x from both sides"`

`4x-2x-12=cancel(2x)cancel(-2x)+4`

`rArr2x-12=4`

`"add 12 to both sides"`

`2xcancel(-12)cancel(+12)=4+12`

`rArr2x=16`

`"divide both sides by 2"`

`(cancel(2) x)/cancel(2)=16/2`

`rArrx=8`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`"left "=4(8-3)=4xx5=20`

`"right "=(2xx8)+4=16+4=20`

`rArrx=8" is the solution"`

Answer 3

`x = 8`

Explanation:

`4⋅(x−3)=2x+4`
Solve for `x`

1) Clear the parentheses by distributing the 4
You can't see what the terms are until you have cleared the parentheses

After you have distributed the 4, you will have this:
`4x - 12 = 2x + 4`

2) Subtract 2x from both sides to get all the x terms together
After you have subtracted, you will get this;
`2x - 12 = 4`

3) Add 12 to both sides to isolate the `2x` term
`2x = 16`

4) Divide both sides by `2` to isolate `x`
`x = 8` `larr` answer

Answer:
`x = 8`
................................

Check

Sub in `8` in the place of `x` in the original equation
`4⋅(x−3)=2   x  +4`
`4⋅(8−3)=2*8  +4`

Solve inside the parentheses
`4⋅(5)=2*8 +4`

Do both multiplications
`20 = 16 + 4`

Add
`20 = 20`

`Check!`