How do you solve $4 ln x = - 2$ $4 ln x=-2$ ?

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Answer 1 · 2016-06-15T07:31:59

$x = \frac{1}{\sqrt{e}}$ $x=1/sqrte$

$4 ln x = - 2$ $4lnx=-2$

$\Leftrightarrow {ln x}^{4} = - 2$ $hArr lnx^4=-2$

$\Leftrightarrow x^{4} = e^{- 2}$ $hArr x^4=e^(-2)$

$\Leftrightarrow x = {(e^{- 2})}^{\frac{1}{4}} = e^{- \frac{1}{2}} = \frac{1}{\sqrt{e}}$ $hArr x=(e^(-2))^(1/4)=e^(-1/2)=1/sqrte$

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